| Rozdanie |
Przeciwnicy |
Kontrakt |
Wist |
Zapis |
Wynik |
|
1
(NS)
|
Magdalena Tomaszewska — Monika Kidoń |
3BA S +3 |
♦2 |
490 |
35.29% |
|
2
(NS)
|
Magdalena Tomaszewska — Monika Kidoń |
2♠ W +1 |
♥K |
-140 |
0.00% |
|
3
(NS)
|
Magdalena Tomaszewska — Monika Kidoń |
2♠ W = |
♥7 |
-110 |
26.47% |
|
4
(EW)
|
Waldemar Majtas — Małgorzata Węglewska |
3♣ S +2 |
♦K |
150 |
26.47% |
|
5
(EW)
|
Waldemar Majtas — Małgorzata Węglewska |
2♠ W +2 |
♣8 |
-170 |
73.53% |
|
6
(EW)
|
Waldemar Majtas — Małgorzata Węglewska |
1BA S -1 |
♥4 |
-50 |
44.12% |
|
7
(NS)
|
Marcin Jankowski — Grzegorz Maguza |
2♠ N -1 |
♠3 |
-100 |
23.53% |
|
8
(NS)
|
Marcin Jankowski — Grzegorz Maguza |
3♣ W +1 |
♠A |
-130 |
23.53% |
|
9
(NS)
|
Marcin Jankowski — Grzegorz Maguza |
3♠ N = |
♦6 |
140 |
52.94% |
|
10
(EW)
|
Danuta Serafinowicz — Agata Duczak |
4♥ N +2 |
♠9 |
680 |
32.35% |
|
11
(EW)
|
Danuta Serafinowicz — Agata Duczak |
1BA E +1 |
♥8 |
-120 |
67.65% |
|
12
(EW)
|
Danuta Serafinowicz — Agata Duczak |
2♥ E +2 |
♦5 |
-170 |
17.65% |
|
13
(NS)
|
Andrzej Łodziński — Agnieszka Jonczyk |
3BA W +3 |
♣J |
-690 |
23.53% |
|
14
(NS)
|
Andrzej Łodziński — Agnieszka Jonczyk |
2♥ S = |
♥J |
110 |
82.35% |
|
15
(NS)
|
Andrzej Łodziński — Agnieszka Jonczyk |
3BA N +1 |
♣9 |
630 |
97.06% |
|
16
(NS)
|
Jerzy Chodnicki — Danuta Zalewska-Bielanik |
4♦ W -1 |
♣4 |
100 |
76.47% |
|
17
(NS)
|
Jerzy Chodnicki — Danuta Zalewska-Bielanik |
4♠ S +1 |
♣K |
450 |
50.00% |
|
18
(NS)
|
Jerzy Chodnicki — Danuta Zalewska-Bielanik |
3BA E +3 |
♠8 |
-490 |
14.71% |
|
19
(EW)
|
Katarzyna Rzepka — Kazimierz Woliński |
2♥ N = |
♣5 |
110 |
44.12% |
|
20
(EW)
|
Katarzyna Rzepka — Kazimierz Woliński |
4♠ E -1 |
♣3 |
100 |
23.53% |
|
21
(EW)
|
Katarzyna Rzepka — Kazimierz Woliński |
2♠ W +3 |
♣6 |
-200 |
29.41% |
|
22
(NS)
|
Agnieszka Kaczmarczyk — Jakub Zieliński |
4♥ N +1 |
♠8 |
450 |
91.18% |
|
23
(NS)
|
Agnieszka Kaczmarczyk — Jakub Zieliński |
3BA N +2 |
♥K |
660 |
88.24% |
|
24
(NS)
|
Agnieszka Kaczmarczyk — Jakub Zieliński |
4♠ N +1 |
♦3 |
450 |
91.18% |
|
25
(NS)
|
Bogdan Kościelny — Tadeusz Rutkowski |
1♠ N -1 |
♣9 |
-50 |
70.59% |
|
26
(NS)
|
Bogdan Kościelny — Tadeusz Rutkowski |
4♠ S = |
♠7 |
620 |
41.18% |
|
27
(NS)
|
Bogdan Kościelny — Tadeusz Rutkowski |
1♠ N +3 |
♥K |
170 |
17.65% |